Rust doesn’t support default parameters in function signatures. And unlike in many languages, there’s no way to simulate them with function overloading. This is frustrating for many new Rustaceans coming from other programming languages, so I want to explain why this is actually a good thing, and how to use the Default trait and struct update syntax to achieve similar results. Default parameters (and function overloading) are not part of object-oriented programming, but they are a common feature of a lot of the programming languages new Rustaceans are coming from.
Rust is not an object oriented programming language. Rust may look like an object-oriented programming language: Types can be associated with “methods,” either “intrinsic” or through “traits.” Methods can often be invoked with C++ or Java-style OOP syntax: map.insert(key, value) or foo.clone(). Just like in an OOP language, this syntax involves a “receiver” argument placed before a . in the caller, called self in the callee. But make no mistake: Though it may borrow some of the trappings, some of the terminology and syntax, Rust is not an object-oriented programming language.